Q:
Suppose I have a sorted array like
[1 2 3 4 5 10 11 17 18 19]
I want to break consecutive blocks into separate arrays:
[1 2 3 4 5]
[10 11]
[17 18 19]
A:
mat2cell(x,1,diff([0,find(diff(x) ~= 1),length(x)]))
Subscribe to:
Post Comments (Atom)
[1 2 3 4 5 10 11 17 18 19]
[1 2 3 4 5]
[10 11]
[17 18 19]
mat2cell(x,1,diff([0,find(diff(x) ~= 1),length(x)]))
3 comments:
Very neat - thank you!!
Hi Siyi,
very nice code, just have one question, if I want to allow one missing spot between consecutive number, what will you do it?
for example:
v=[1 2 3 5 6 7 11 12 13 15 16 18 19 21]
want to break down to [1 2 3 4 6 7],[11 12 13 15 16 18 19 21].
Thanks. TY
find a typo here, it is actually [1 2 3 5 6 7] and [11 12 13 15 16 18 19 21].
Post a Comment